下列程序用dp的方式完成了这个任务，请完善程序
#include <bits/stdc++.h>
using namespace std;
int main()
{
vector<string> prefix;
string p,str;
while (true)
{
cin >> p;
if (_____(1)______) break;
prefix.push_back(p);
}
cin >> str;
int len = (int)str.length();
vector<bool> dp(len + 1, false);
______(2)_______;
for (int i = 0; i < len; i++)
{
if (dp[i])
{
for (int j = 0; j < prefix.size(); j++)
{
bool isMatched = true;
for (int k = 0; k < prefix[j].length(); k++)
{
if (______(3)______)
{
isMatched = false;
break;
}
}
if (isMatched) dp[______(4)______] = true;
}
}
}
for (int i = len; i >= 0; i--)
{
if (____(5)______)
{
cout << i << endl;
return 0;
}
}
return 0;
}